### Block on a Table

(a) Just plug in Newton's 2nd law:

$a = \frac{F}{m}=\frac{3.8N}{5.5kg}=0.69\frac{m}{s^{2}}.$
(b)Use v=at:
$t=\frac{v_{f}}{a}=\frac{5.2\frac{m}{s}}{0.69\frac{m}{s^{2}}}=7.5s.$
(c) Again formula from kinematics:
$x=\frac{1}{2}at^{2}=\frac{1}{2}(0.69\frac{m}{s^{2}})(7.5s)^{2}=20m.$